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Question:

Balance the following chemical equations:

(a) HNO_{3} + Ca(OH)_{2} → Ca(NO_{3})_{2} + H_{2}O

(b) NaOH + H_{2}SO_{4} → Na_{2}SO_{4} + H_{2}O

(c) NaCl + AgNO_{3} → AgCl + NaNO_{3}

(d) BaCl_{2} + H_{2}SO_{4} → BaSO_{4} + HCl

Answer:

(a)- The number of atoms of different elements present in the given unbalanced equation is as follows:

First balance hydrogen by multiply 2 in the reactant side and 2 in the product side as shown below:

2 HNO_{3} + Ca(OH)_{2} → Ca(NO_{3})_{2} + 2 H_{2}O

The number of atoms of different elements present in the given balanced equation is as follows:

**Therefore, the correct answer is 2 HNO _{3 }+ Ca(OH)_{2 }→ Ca(NO_{3})_{2 }+ 2H_{2}O.**

(b)- The number of atoms of different elements present in the given unbalanced equation is as follows:

First balance sodium by multiply 2 in the reactant side as shown below:

2 NaOH + H_{2}SO_{4} → Na_{2}SO_{4} + H_{2}O

Now, balance hydrogen by multiply 2 in the product side as shown below:

2 NaOH + H_{2}SO_{4} → Na_{2}SO_{4} + 2 H_{2}O

The number of atoms of different elements present in the given balanced equation is as follows:

**Therefore, the correct answer is 2NaOH + H _{2}SO_{4}→Na_{2}SO_{4 }+ 2H_{2}O.**

(c)- The number of atoms of different elements present in the given unbalanced equation is as follows:

The number of atoms of each element is the same in reactant as in the product.

**Therefore, the correct answer is NaCl + AgNO _{3 }→ AgCl + NaNO_{3}.**

(d)- The number of atoms of different elements present in the given unbalanced equation is as follows:

First, balance hydrogen by multiply 2 in the product side as shown below:

BaCl_{2} + H_{2}SO_{4} → BaSO_{4} + 2 HCl

The number of atoms of different elements present in the given balanced equation is as follows:

**Therefore, the correct answer is BaCl _{2 }+ H_{2}SO_{4 }→ BaSO_{4 }+ 2HCl.**

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