Chapter 2: Acids, Bases and Salts

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Acids,Bases, and Salts


10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be:

(a) 4 mL

(b) 8 mL

(c) 12 mL

(d) 16 mL


When an acid reacts with a base, the salt will form along with water. Such a reaction is called a neutralisation reaction.

In the question, it is given that:

10 mL of sodium hydroxide required = 8 mL HCl

∴ 20 mL of sodium hydroxide required =

 =frac { 8mL }{ 10mL } 	imes 20mL=16mL


Therefore, the correct answer is (d) 16 mL

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