### Chapter 1: Real Numbers

Q
##### Real Numbers Solutions

Question:

An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

Solutions: Given, number of army contingent members = 616

Number of army band members = 32

If the two groups have to march in the same column, we have to find out the highest common factor between the two groups.

HCF (616, 32)  gives the maximum number of columns in which they can march.

By using Euclid’s algorithm to find their HCF, we get,

Solutions: Given, number of army contingent members = 616

Number of army band members = 32

If the two groups have to march in the same column, we have to find out the highest common factor between the two groups.

HCF (616, 32)  gives the maximum number of columns in which they can march.

By using Euclid’s algorithm to find their HCF, we get,

Since, 616 is greater than 32, therefore,

616 = 32 × 19 + 8

Since, remainder 8 ≠ 0,

We consider new dividend 32 and new divisor 8, and again using Euclid’s division lemma, we get,

32 = 8 × 4 + 0

Now we have got a remainder as 0. Since the divisor at this stage is 8. Therefore, HCF (616, 32) = 8.

So, the maximum number of columns in which they can march is 8.

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