Chapter 1: Real Numbers

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Q
Real Numbers Solutions

Question:

Given that HCF (306, 657) = 9, find LCM (306, 657).

Answer:

Solutions: Given that HCF of 306 and 657 is  9. 

We know that

LCM × HCF = product of two numbers.
LCM × 9 = 306 × 657


LCM = frac{306	imes657}{9}  = 34 × 657 = 22338

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