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Question:
The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and graphically.
Answer:
Solution: Suppose the cost of 1 cricket bat is Rs x and the cost of 1 cricket ball is Rs y.
According to given conditions, we have
3x + 6y = 3900 x + 2y = 1300 ... (I)
And x + 3y = 1300 (II)
x 
0 
1300 
y 
650 
0 
For equation x + 2y = 1300, we have the following points which lie on the line.
x 
0 
1300 
y 
0

For equation x + 3y = 1300, we have the following points which lie on the line.
We plot the points for both of the equations x + 2y = 1300 & x + 3y = 1300. The following is the graphical representation of the given situation.
These two lines intersect at B (1300,0).
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