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Question:

A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s^{-2}, with what velocity will it strike the ground? After what time will it strike the ground?

Answer:

Distance covered by the ball, S = 20 m

Acceleration, a = 10 ms^{-2}

Initial velocity, u = 0 (since the ball was initially at rest)

Let final velocity of the ball with which it strikes the ground is v.

According to the third equation of motion:

According to the first equation of motion:

Where,

Time, t is taken by the ball to strike the ground is,

Hence the ball strikes the ground after 2 s with a velocity of 20 m/s.

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