Chapter - 3 Gravitation

Q&A -Ask Doubts and Get Answers

Q
Gravitation

Question:

A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Answer:

Given:

u = Initial velocity of the stone = 0

v = Final velocity of the stone = ?

s = Height of the tower = 19.6 m

g = Acceleration due to gravity = 9.8 ms^{-2}

Using the third equation of motion,

v^2 - u^2 = 2as

v^2 - (0)^2 = 2 	imes 19.6 	imes 9.8

v^2 = 384.16

v = 19.6 ms^{-1}

Hence, the velocity of the stone just before touching the ground is 19.6 ms^{-1}.


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