Chapter - 2 Force and Laws of Motion

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Q
Force and Laws of Motion

Question:

A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20 s. Find its acceleration. Find the force acting on it if its mass is 7 tonnes (Hint: 1 tonne = 1000 kg.) 

Answer:

Given:

u = 0 m/s

S = 400 m

t = 20 s

m = 7\ tonnes = 7 \times 1000\ kg = 7000\ kg

To Find: a = ? and F = ?

For acceleration (a):

Using 2nd equation of motion

S = ut + \frac{1}{2} a{t}^{2}

400 = 0 \times 20 + \frac{1}{2}a(20)^2

400 = \frac{1}{2} \times a \times 400

a = 2\ m/s^2

For force (F) :

F = ma

F = 7000 \times 2

F = 14000 N

 


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