Chapter - 2 Force and Laws of Motion

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Force and Laws of Motion

Question:

An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

Answer:

Given: Mass of the object, m = 100 kg

Initial velocity of the object, u = 5 m/s

Final velocity of the object, v = 8 m/s

Time taken, t = 6 s

Initial momentum of the object = mu

Initial momentum of the object = 100 	imes 5

Initial momentum of the object = 500 kgm/s

Now,

Final momentum of the object = mv

Final momentum of the object = 100 	imes 8

Final momentum of the object = 800 kgm/s

For calculating the force on the object, we use the second law of motion.

According to Newton's second law of motion: External force exerted on an object is proportional to the rate of change of momentum.

Therefore,

F = frac{Change in momentum}{Time}

F = frac{mv - mu}{t}

F = frac{800 - 500}{6}

F = frac{300}{6}

F = 50 N

Force exerted on the object is 50 N.


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