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Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?
(a) From end A to end B
Distance covered by Joseph while jogging from A to B = 300 m
Time taken to cover that distance = 2 min 30 seconds = 150 s
Total distance covered = 300 m
Total time taken = 170 s
Displacement = shortest distance between A and B = 300 m
Time interval = 150 s
The average speed and average velocity of Joseph for jogging from
A to B are the same and equal to 2 m/s
(b) From end A to end C
Total distance covered = Distance from A to B + Distance from B to C = 300 + 100 = 400 m
Total time taken = Time taken to travel from A to B + Time taken to travel from B to C = 150 + 60 = 210 s
Displacement from A to C = AC = AB - BC = 300 - 100 = 200 m
Time interval = Time taken to travel from A to B + Time taken to travel from B to C
Time interval = 150 s + 60 s = 210 s
The average speed of Joseph from A to C is 1.90 m/s and his average velocity is 0.95 m/s.
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