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A ball is thrown vertically upwards with a velocity of 49 m/s.
(i) the maximum height to which it rises,
(ii) the total time it takes to return to the surface of the earth.
Initial velocity, = 49 m/s
Final speed at maximum height = 0
Acceleration due to gravity g = -9.8 m/s² (g is negative as the ball is thrown up).
(i) Using the third equation of motion,
By substituting all the values in the above equation, we get
(ii) Let t be the time taken by the ball to reach the height 122.5 m.
Using the first equation of motion.
Time of ascent = Time of descent
Therefore, total time taken by the ball to return = 5 + 5 = 10 s
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